Virtual bremsstrahlung in proton-proton scattering below the pion-production threshold

2000 ◽  
Vol 61 (6) ◽  
Author(s):  
J. G. Messchendorp ◽  
J. C. S. Bacelar ◽  
M. J. van Goethem ◽  
M. N. Harakeh ◽  
M. Hoefman ◽  
...  
1999 ◽  
Vol 83 (20) ◽  
pp. 4017-4020 ◽  
Author(s):  
H. Huisman ◽  
J. C. S. Bacelar ◽  
M. J. van Goethem ◽  
M. N. Harakeh ◽  
M. Hoefman ◽  
...  

1988 ◽  
Vol 41 (1) ◽  
pp. 31 ◽  
Author(s):  
JA Niskanen ◽  
AW Thomas

We examine the effect of the coupled N.6. inelastic channel on charge symmetry breaking in the np system. Our calculation includes the effects of mass splitting for the nucleon and delta multiplets in the channel coupling potentials. The results suggest that such effects become increasingly important at about 500 MeV laboratory energy.


2009 ◽  
Vol 24 (02n03) ◽  
pp. 539-543
Author(s):  
L. JOULAEIZADEH ◽  
J. BACELAR ◽  
M. ESLAMI-KALANTARI ◽  
I. GAŠPARIĆ ◽  
N. KALANTAR-NAYESTANAKI ◽  
...  

In order to study the role of pions and clustering phenomena in nuclei, two experiments have been performed using the AGOR accelerator facility. In collisions of two nuclei a pion and a fused nucleus were produced. The examined reactions were 4He(3He, π0)7Be and 6Li(4He, π0)10B at beam energies about 10 MeV above the coherent pion production threshold (256 MeV and 236.4 MeV, respectively). Since the available energy is well below the pion production threshold in an elementary nucleon-nucleon process, a highly coherent mechanism is needed. We identified the reaction by measuring the fused system in the magnetic spectrometer and the produced neutral pions in the Plastic Ball detection system with large acceptance. Our experimental setup provided the exclusive cross sections by identifying all products in overdetermined kinematics. Here we present the preliminary results of the analysis for the second reaction. Angular distribution of neutral pions will be discussed.


1997 ◽  
Vol 393 (3-4) ◽  
pp. 295-300 ◽  
Author(s):  
K Maruyama ◽  
K Niki ◽  
Y Sumi ◽  
T Emura ◽  
I Endo ◽  
...  

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