scholarly journals Method to Derive the Hamiltonian of Acoustic Topological Crystalline Insulators

2021 ◽  
Vol 15 (6) ◽  
Author(s):  
An-Yang Guan ◽  
Zhang-Zhao Yang ◽  
Xin-Ye Zou ◽  
Jian-Chun Cheng
2021 ◽  
pp. 127469
Author(s):  
Muhammad Bilal ◽  
Syed Muhammad Alay-e-Abbas ◽  
Michael Sluydts ◽  
Javaria Batool ◽  
Amel Laref ◽  
...  

2019 ◽  
Vol 1 (1) ◽  
Author(s):  
Tan Zhang ◽  
Changming Yue ◽  
Tiantian Zhang ◽  
Simin Nie ◽  
Zhijun Wang ◽  
...  

2015 ◽  
Vol 14 (3) ◽  
pp. 318-324 ◽  
Author(s):  
Ilija Zeljkovic ◽  
Yoshinori Okada ◽  
Maksym Serbyn ◽  
R. Sankar ◽  
Daniel Walkup ◽  
...  

2018 ◽  
Vol 8 (3) ◽  
Author(s):  
Eslam Khalaf ◽  
Hoi Chun Po ◽  
Ashvin Vishwanath ◽  
Haruki Watanabe

Author(s):  
Seyyed Hosein Ganjipour

We theoretically study the Ruderman-Kittle-Kasuya-Yosida (RKKY) interaction between two magnetic impurities embedded on the (001) surface of a topological crystalline insulator (TCI), using the Green’s function method. Highly anisotropic band structure of TCI, gives rise to a highly anisotropic magnetic exchange coupling. We show that the interaction is oscillatory; the amplitude and wavelength of oscillations have angular dependence arising from the anisotropy of the surface state band structure. The spatial configurations of the magnetic impurities can also dramatically change the quality and quantity of the RKKY interaction. We find a strong anisotropy of the exchange interaction and the magnetic ground state of two magnetic adatoms can be tuned by changing the rotational configuration of impurities. It is found that the three types of interactions contribute to the magnetic exchange coupling in the (001) TCI surfaces: the Heisenberg, Dzyaloshinsky-Moriya, and Ising types. Our results will open up a new route toward spintronics based on TCIs.


2020 ◽  
Vol 101 (4) ◽  
Author(s):  
Huaqing Huang ◽  
Yong-Shi Wu ◽  
Feng Liu

Small ◽  
2015 ◽  
Vol 11 (36) ◽  
pp. 4613-4624 ◽  
Author(s):  
Qisheng Wang ◽  
Feng Wang ◽  
Jie Li ◽  
Zhenxing Wang ◽  
Xueying Zhan ◽  
...  

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